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# An Aeroplane Take 1 Hour Less for a Journey of 1200 Km If Its Speed is Increased by 100 Km/Hr from Its Usual Speed. Find Its Usual Speed. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

#### Question

An aeroplane take 1 hour less for a journey of 1200 km if its speed is increased by 100 km/hr from its usual speed. Find its usual speed.

#### Solution

Let the usual speed of aero plane be x km/hr. Then,

Increased speed of the aero plane = (x + 100)km/hr

Time taken by the aero plane under usual speed to cover 1200 km = 1200/xhr

Time taken by the aero plane under increased speed to cover 1200 km = 1200/(x+100)hr

Therefore,

1200/x-1200/(x+100)=1

(1200(x+100)-1200x)/(x(x+100x))=1

(1200x+120000-1200x)/(x^2+100x)=1

12000/(x^2+100x)=1

120000 = x2 + 100x

x2 + 100x - 120000 = 0

x2 - 300x + 400x - 120000 = 0

x(x - 300) + 400(x - 300) = 0

(x - 300)(x + 400) = 0

So, either

x - 300 = 0

x = 300

Or

x + 400 = 0

x = -400

But, the speed of the aero plane can never be negative.

Hence, the usual speed of train is x = 300 km/hr

Is there an error in this question or solution?

#### APPEARS IN

Solution An Aeroplane Take 1 Hour Less for a Journey of 1200 Km If Its Speed is Increased by 100 Km/Hr from Its Usual Speed. Find Its Usual Speed. Concept: Solutions of Quadratic Equations by Factorization.
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