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A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

Question

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train.

Solution

Let the original speed of train be x km/hr. Then,

Increased speed of the train = (x + 5)km/hr

Time taken by the train under usual speed to cover 360 km = 360/xhr

Time taken by the train under increased speed to cover 360 km = 360/(x+5)hr

Therefore,

360/x-360/(x+5)=1

(360(x+5)-360x)/(x(x+5))=1

(360x+1800-360x)/(x^2+5x)=1

1800/(x^2+5x)=1

1800 = x2 + 5x

x2 + 5x - 1800 = 0

x2 - 40x + 45x - 1800 = 0

x(x - 40) + 45(x - 40) = 0

(x - 40)(x + 45) = 0

So, either

x - 40 = 0

x = 40

Or

x + 45 = 0

x = -45

But, the speed of the train can never be negative.

Hence, the original speed of train is x = 40 km/hr

Is there an error in this question or solution?

APPEARS IN

NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 4: Quadratic Equations
Ex.4.30 | Q: 8 | Page no. 88
Solution A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of the train. Concept: Solutions of Quadratic Equations by Factorization.
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