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A Passenger Train Takes One Hour Less for a Journey of 150 Km If Its Speed is Increased by 5 Km/Hr from Its Usual Speed. Find the Usual Speed of the Train. - Mathematics

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Question

A passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from its usual speed. Find the usual speed of the train.

Solution

Let the usual speed of train be x km/hr then

Increased speed of the train = (x + 5)km/hr

Time taken by the train under usual speed to cover 150km = `150/x`hr

Time taken by the train under increased speed to cover 150km = `150/(x + 5)`hr

Therefore,

`150/x-150/(x+5)=1`

`(150(x+5)-150x)/(x(x+5))=1`

`(150x+750-150)/(x^2+5x)=1`

`750/(x^2+5x)=1`

750 = x2 + 5x

x2 + 5x - 750 = 0

x2 - 25x + 30x - 750 = 0

x(x - 25) + 30(x - 25) = 0

(x - 25)(x + 30) = 0

So, either

x - 25 = 0

x = 25

Or

x + 30 = 0

x = -30

But, the speed of the train can never be negative.

Hence, the usual speed of train is x = 25km/hr

  Is there an error in this question or solution?
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 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.8 | Q: 4 | Page no. 58
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.8 | Q: 4 | Page no. 58
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A Passenger Train Takes One Hour Less for a Journey of 150 Km If Its Speed is Increased by 5 Km/Hr from Its Usual Speed. Find the Usual Speed of the Train. Concept: Solutions of Quadratic Equations by Factorization.
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