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A Girls is Twice as Old as Her Sister. Four Years Hence, the Product of Their Ages (In Years) Will Be 160. Find Their Present Ages. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

Question

A girls is twice as old as her sister. Four years hence, the product of their ages (in years) will be 160. Find their present ages.

Solution

Let the present age of girl be x years then, age of her sister x/2 years

Then, 4 years later, age of girl (x + 4) years and her sister’s age be (x/2+4)Years

Then according to question,

(x+4)(x/2+4)=160

(x + 4)(x + 8) = 160 x 2

x2 + 8x + 4x + 32 = 320

x2 + 12x + 32 - 320 = 0

x2 + 12x - 288 = 0

x2 - 12x + 24x - 288 = 0

x(x - 12) + 24(x - 12) = 0

(x - 12)(x + 24) = 0

So, either

x - 12 = 0

x = 12

Or

x + 24 = 0

x = -24

But the age never be negative

Therefore, when x = 12 then

x/2=12/2=6

Hence, the present age of girl be 12 years and her sister’s age be 6 years.

Is there an error in this question or solution?

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Solution A Girls is Twice as Old as Her Sister. Four Years Hence, the Product of Their Ages (In Years) Will Be 160. Find Their Present Ages. Concept: Solutions of Quadratic Equations by Factorization.
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