Share

Books Shortlist

# A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

#### Question

A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.

#### Solution

et the cost price of article be Rs. x.

Then, gain percent = x

Therefore, the selling price of article

=(x+x/100xx x)

=(x^2+100x)/100

It is given that

(x^2+100x)/100=24

x2 + 100x = 2400

x2 + 100x - 2400 = 0

x2 + 120x - 20x - 2400 = 0

x(x + 120) - 20(x + 120) = 0

(x + 120)(x - 20) = 0

x + 120 = 0

x = -120

Or

x - 20 = 0

x = 20

Because cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the cost price of article be x = Rs. 20

Is there an error in this question or solution?

#### APPEARS IN

Solution A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. Concept: Solutions of Quadratic Equations by Factorization.
S