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A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. - Mathematics

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Question

A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.

Solution

et the cost price of article be Rs. x.

Then, gain percent = x

Therefore, the selling price of article

`=(x+x/100xx x)`

`=(x^2+100x)/100`

It is given that

`(x^2+100x)/100=24`

x2 + 100x = 2400

x2 + 100x - 2400 = 0

x2 + 120x - 20x - 2400 = 0

x(x + 120) - 20(x + 120) = 0

(x + 120)(x - 20) = 0

x + 120 = 0

x = -120

Or

x - 20 = 0

x = 20

Because cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the cost price of article be x = Rs. 20

  Is there an error in this question or solution?

APPEARS IN

 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Q: 3 | Page no. 80
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Q: 3 | Page no. 80
Solution A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. Concept: Solutions of Quadratic Equations by Factorization.
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