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A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. - CBSE Class 10 - Mathematics

ConceptSolutions of Quadratic Equations by Factorization

Question

A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.

Solution

et the cost price of article be Rs. x.

Then, gain percent = x

Therefore, the selling price of article

=(x+x/100xx x)

=(x^2+100x)/100

It is given that

(x^2+100x)/100=24

x2 + 100x = 2400

x2 + 100x - 2400 = 0

x2 + 120x - 20x - 2400 = 0

x(x + 120) - 20(x + 120) = 0

(x + 120)(x - 20) = 0

x + 120 = 0

x = -120

Or

x - 20 = 0

x = 20

Because cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the cost price of article be x = Rs. 20

Is there an error in this question or solution?

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Solution A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. Concept: Solutions of Quadratic Equations by Factorization.
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