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The Sum of the Squares of Two Consecutive Multiples of 7 is 637. Find the Multiples. - Mathematics

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Question

The sum of the squares of two consecutive multiples of 7 is 637. Find the multiples.

Solution

Let one of the number be 7x then the other number be 7(x + 1).

Then according to question,

\[\left( 7x \right)^2 + \left[ 7\left( x + 1 \right) \right]^2 = 637\]

\[ \Rightarrow 49 x^2 + 49( x^2 + 2x + 1) = 637\]

\[ \Rightarrow 49 x^2 + 49 x^2 + 98x + 49 - 637 = 0\]

\[ \Rightarrow 98 x^2 + 98x - 588 = 0\]

\[ \Rightarrow x^2 + x - 6 = 0\]

\[ \Rightarrow x^2 + 3x - 2x - 6 = 0\]

\[ \Rightarrow x(x + 3) - 2(x + 3) = 0\]

\[ \Rightarrow (x - 2)(x + 3) = 0\]

\[ \Rightarrow x - 2 = 0 \text { or } x + 3 = 0\]

\[ \Rightarrow x = 2 \text { or } x = - 3\]

Since, the numbers are multiples of 7,

Therefore, one number = 7 × 2 =14.

Then another number will be \[7(x + 1) = 7 \times 3 = 21\]

Thus, the two consecutive multiples of 7 are 14 and 21.

  Is there an error in this question or solution?
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 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 38 | Page no. 53
 RD Sharma Solution for Class 10 Maths (2018 (Latest))
Chapter 4: Quadratic Equations
Ex. 4.7 | Q: 38 | Page no. 53
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The Sum of the Squares of Two Consecutive Multiples of 7 is 637. Find the Multiples. Concept: Solutions of Quadratic Equations by Completing the Square.
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