Advertisement Remove all ads

Six Year Before, the Age of Mother Was Equal to the Square of Her Son'S Age. Three Year Hence, Her Age Will Be Thrice the Age of Her Son Then. Find the Present Ages of the Mother and Son. - Algebra

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

Six year before, the age of mother was equal to the square of her son's age. Three year hence, her age will be thrice the age of her son then. Find the present ages of the mother and son.

Advertisement Remove all ads

Solution

Suppose, the age of the son six year before was x
∴ mother’s age six year before was x2
∴ present age of the son is (x + 6) and
present age of the mother is (x2 + 6)
Three years hence, son’s age will be (x + 9) and mother’s age will be (x2 + 9)
by given condition,
x2 + 9 = 3(x + 9)
∴ x2 - 3x + 9 - 27 = 0
∴ x2 - 3x - 18 = 0
∴ (x - 6) (x + 3) = 0
∴ x = 6 or x = -3
But age cannot be negative ∴ x ≠ -3
∴ son’s present age = x + 6 = 6 + 6 = 12 years.
mother’s present age = x2 + 6 = 36 + 6 = 42 years.

Concept: General Term of an Arithmetic Progression
  Is there an error in this question or solution?
Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×