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Six Taps Can Fill an Empty Cistern in 8 Hours. How Much More Time Will Be Taken, If Two Taps Go Out of Order? Assume, All the Taps Supply Water at the Same Rate. - Mathematics

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Sum

Six taps can fill an empty cistern in 8 hours. How much more time will be taken, if two taps go out of order? Assume, all the taps supply water at the same rate.

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Solution

Total no. of taps = 6

Out of order taps = 2

Taps in working condition = 6  –  2 = 4

6 taps can fill an empty cistern in = 8 hours

1 tap can fill an empty cistern in = 6 x 8 hours

4 taps can fill an empty cistern in = `48/4` = 12 hours

More time taken when 2 taps are out of order = 12 – 8 = 4 hour

Concept: Concept for Unitary Method (With Only Direct Variation Implied)
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 10 Direct and Inverse Variations
Exercise 10 (D) | Q 3 | Page 129
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