Sum
`(sin A)/(1 + cos A) + (1 + cos A)/(sin A)` = 2 cosec A
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Solution
LHS = `((sin^2 A + ( 1 + cos A)^2)/((1 + cos A)sin A))`
= `(sin^2 A + 1 + cos^2 A + 2 cos A)/((1 + cos A) sin A)`
= `(1 + 1 + 2 cos A)/((1 + cos A) sin A)`
= `(2(1 + cos A))/((1 + cos A)sin A)`
= 2 cosec A
= RHS
Hence proved.
Concept: Trigonometric Identities
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