# Simplify the Following: (5^(N+3)-6xx5^(N+1))/(9xx5^X-2^2xx5^N) - Mathematics

Simplify the following:

(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)

#### Solution

(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)

=(5^(n+1)(5^2-6))/(5^n(9xx2^2))

=(5^nxx5xx(25-6))/(5^n(9-4))

=(5xx19)/5

= 19

Concept: Laws of Exponents for Real Numbers
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#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 2 Exponents of Real Numbers
Exercise 2.1 | Q 7.3 | Page 12