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Simplify the following:
`(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)`
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Solution
`(5^(n+3)-6xx5^(n+1))/(9xx5^x-2^2xx5^n)`
`=(5^(n+1)(5^2-6))/(5^n(9xx2^2))`
`=(5^nxx5xx(25-6))/(5^n(9-4))`
`=(5xx19)/5`
= 19
Concept: Laws of Exponents for Real Numbers
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