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Simplify the Following: `(3^Nxx9^(N+1))/(3^(N-1)Xx9^(N-1))` - Mathematics

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ConceptLaws of Exponents for Real Numbers

Question

Simplify the following:

`(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))`

Solution

`(3^nxx9^(n+1))/(3^(n-1)xx9^(n-1))`

`=(3^nxx(3^2)^(n+1))/(3^(n-1)xx(3^2)^(n-1))`

`=(3^nxx3^(2n+2))/(3^(n-1)xx3^(2n-2))`

`=3^(n+2n+2)/3^(n-1+2n-2)`

`=3^(3n + 2)/3^(3n-3)`

`=3^(3n+2-3n+3)`

= 35

= 243

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Solution Simplify the Following: `(3^Nxx9^(N+1))/(3^(N-1)Xx9^(N-1))` Concept: Laws of Exponents for Real Numbers.
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