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Simplify : 8^3a Xx 2^5 Xx 2^(2a) / 4 Xx 2^(11a) Xx 2^(-2a) - Mathematics

Sum

Simplify :
`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`

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Solution

`[ 8^3a xx 2^5 xx 2^(2a) ]/[ 4 xx 2^(11a) xx 2^(-2a) ]`

= `[(2^3)^(3a) xx 2^5 xx 2^(2a) ]/[ 2^2 xx 2^(11a) xx 2^(-2a)]`

=`[ 2^( 3 xx 3a ) xx 2^5 xx 2^(2a)]/[ 2^2 xx 2^(11a) xx 2^(-2a)]`

= `[2^(9a) xx 2^5 xx 2^(2a)]/[ 2^2 xx 2^(11a) xx 2^(-2a)]`

= `2^[9a + 5 + 2a - 2 - 11a + 2a]`

= `2^[ 2a + 3 ]`

Concept: Laws of Exponents
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APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 7.1 | Page 98
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