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Simplify : 5^( N + 3 ) - 6 Xx 5^( N + 1 )/9 Xx 5^N - 5^N Xx 2^2 - Mathematics

Sum

Simplify :
`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

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Solution

`[ 5^( n + 3 ) - 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

= `[ 5^( n + 1 ) xx 5^2- 6 xx 5^( n + 1 )]/[ 9 xx 5^n - 5^n xx 2^2 ]`

= `[ 5^( n + 1 ) xx ( 5^2 - 6 )]/[ 5^n xx ( 9 - 4 )]`

= `[ 5^1 xx 19 ]/5`

= 19

Concept: Laws of Exponents
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APPEARS IN

Selina Concise Mathematics Class 9 ICSE
Chapter 7 Indices (Exponents)
Exercise 7 (A) | Q 2.3 | Page 98
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