SSC (English Medium) Class 8Maharashtra State Board
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Simplify : 4 X 2 − 11 X + 6 16 X 2 − 9 - SSC (English Medium) Class 8 - Mathematics

Question

Simplify :

$\frac{4 x^2 - 11x + 6}{16 x^2 - 9}$

Solution

It is known that,

$a^2 - b^2 = \left( a + b \right)\left( a - b \right) ; a^3 - b^3 = \left( a - b \right)\left( a^2 + ab + b^2 \right)$

$\ \frac{4 x^2 - 11x + 6}{16 x^2 - 9}$

$= \frac{4 x^2 - 8x - 3x + 6}{\left( 4x \right)^2 - \left( 3 \right)^2}$

$= \frac{4x\left( x - 2 \right) - 3\left( x - 2 \right)}{\left( 4x + 3 \right)\left( 4x - 3 \right)}$

$= \frac{\left( 4x - 3 \right)\left( x - 2 \right)}{\left( 4x + 3 \right)\left( 4x - 3 \right)}$

$= \frac{x - 2}{4x + 3}$

Is there an error in this question or solution?

APPEARS IN

Balbharati Solution for Balbharati Class 8 Mathematics (2019 to Current)
Chapter 6: Factorisation of Algebraic expressions
Practice Set 6.4 | Q: 6 | Page no. 33
Solution Simplify : 4 X 2 − 11 X + 6 16 X 2 − 9 Concept: Factors of A3 - B3.
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