Answer 1

\[\frac{16 m^3 y^2}{4 m^2 y}\]
\[ = \frac{16 \times m \times m \times m \times y \times y}{4 \times m \times m \times y}\]
\[ = 4 m^{(3 - 2)} y^{(2 - 1)} \]
\[ = 4my\]