#### Question

A man tosses two different coins (one of Rs 2 and another of Rs 5) simultaneously. What is the probability that he gets:** **

at most one head?

#### Solution

When two coins are tosses simultaneously , the possiuble outcomes are {(H,H)(H,T)(T,H)(T,T)}

n(s)=4

The outcomes favourable to the event E,' at most one head are {(T,H)(H,T)(T,T)}

So, the number of outcomes favourable to E is 3=n(E)

Therefore, p(E)=`(n(E))/(n(s))=3/4`

Is there an error in this question or solution?

Solution A Man Tosses Two Different Coins (One of Rs 2 and Another of Rs 5) Simultaneously. What is the Probability that He Gets: At Most One Head? Concept: Simple Problems on Single Events.