#### Question

A bag contains 10 red balls, 16 white balls and 8 green balls. A ball is drawn out of the bag at random. What is the probability that the ball drawn will be:

neither red nor green?

#### Solution

Total number of possible outcomes = 10+16+8=34 balls

n(s)=34

Favorable outcomes for neither a red nor a green ball=favourable outcomes for white ball number of favorable outcomes for white ball=16=n(E)

Probability for not drawing a red or green ball= `(n(E))/(n(s))=16/34=8/17 `

Is there an error in this question or solution?

Solution A Bag Contains 10 Red Balls, 16 White Balls and 8 Green Balls. a Ball is Drawn Out of the Bag at Random. What is the Probability that the Ball Drawn Will Be: Neither Red Nor Green? Concept: Simple Problems on Single Events.