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Solution for If X = 2at, Y = At2, Where a is a Constant, Then Find D 2 Y D X 2 at X = 1 2 ? - CBSE (Commerce) Class 12 - Mathematics

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Question

If x = 2aty = at2, where a is a constant, then find \[\frac{d^2 y}{d x^2} \text { at }x = \frac{1}{2}\] ?

Solution

Here,

\[x = 2\text { at and y } = a t^2 \]
\[\text { Differentiating w . r . t . t, we get }\]
\[\frac{d x}{d t} = 2\text { a and} \frac{d y}{d t} = 2\text { at } \]
\[ \therefore \frac{d y}{d x} = \frac{2at}{2a} = t\]
\[\text { Differentiating again w . r . t . t, we get} \]
\[\frac{d^2 y}{d x^2} = 1 \times \frac{dt}{dx} = \frac{1}{2a}\]
\[\text { Now,} \left[ \frac{d^2 y}{d x^2} \right]_{x = \frac{1}{2}} = \frac{1}{2a}\]

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Solution for question: If X = 2at, Y = At2, Where a is a Constant, Then Find D 2 Y D X 2 at X = 1 2 ? concept: Simple Problems on Applications of Derivatives. For the courses CBSE (Commerce), CBSE (Arts), PUC Karnataka Science, CBSE (Science)
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