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# Differentiate E Tan − 1 √ X ? - CBSE (Arts) Class 12 - Mathematics

ConceptSimple Problems on Applications of Derivatives

#### Question

Differentiate $e^{\tan^{- 1}} \sqrt{x}$ ?

#### Solution

$\text{ Let } y = e^{{\tan^{- 1}} \sqrt{x}}$

Differentiate it with respect to x we get,

$\frac{d y}{d x} = \frac{d}{dx}\left( e^{\tan^{- 1}} \sqrt{x} \right)$

$= e^{{\tan^{- 1}} \sqrt{x}} \frac{d}{dx}\left( \tan^{- 1} \sqrt{x} \right) ....\left[ \text{ Using chain rule} \right]$

$= e^{{\tan^{- 1}} \sqrt{x}} \times \frac{1}{1 + \left( \sqrt{x} \right)^2}\frac{d}{dx}\left( \sqrt{x} \right)$

$= \frac{e^{{\tan^{- 1}} \sqrt{x}}}{1 + x} \times \frac{1}{2\sqrt{x}}$

$= \frac{e^{{\tan^{- 1}} \sqrt{x}}}{2\sqrt{x}\left( 1 + x \right)}$

$So, \frac{d}{dx}\left( e^{{\tan^{- 1}} \sqrt{x}} \right) = \frac{e^{{\tan^{- 1}} \sqrt{x}}}{2\sqrt{x}\left( 1 + x \right)}$

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Solution Differentiate E Tan − 1 √ X ? Concept: Simple Problems on Applications of Derivatives.
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