#### Question

A particle in S.H.M. has a period of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.

#### Solution

A particle in SHM has a period of 2 seconds and an amplitude of 10 cm. When it is at 4 cm from its positive extreme position, the displacement (x) of the particle is 10 - 4 = 6 cm.

Acceleration = ω^{2}.x (in magnitude)

`=((2pi)/T)^2x`

`=(4pi^2)/(2)^2xx 6`

= 59.16 cm/s^{2}

Thus, the acceleration of the particle at 4 cm from its positive extreme position is 59.16 cm/s^{2}.

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#### APPEARS IN

Solution Calculate the Acceleration When It is at 4 Cm from Its Positive Extreme Position. Concept: Simple Harmonic Motion.