HSC Science (Computer Science) 12th Board ExamMaharashtra State Board
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Solution for Calculate the Acceleration When It is at 4 Cm from Its Positive Extreme Position. - HSC Science (Computer Science) 12th Board Exam - Physics

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Question

A particle in S.H.M. has a period of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.

Solution

A particle in SHM has a period of 2 seconds and an amplitude of 10 cm. When it is at 4 cm from its positive extreme position, the displacement (x) of the particle is 10 - 4 = 6 cm.

Acceleration = ω2.x (in magnitude)

`=((2pi)/T)^2x`

`=(4pi^2)/(2)^2xx 6`

= 59.16 cm/s2

 Thus, the acceleration of the particle at 4 cm from its positive extreme position is 59.16 cm/s2.

  Is there an error in this question or solution?

APPEARS IN

 2014-2015 (March) (with solutions)
Question 2.5 | 2.00 marks

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Solution Calculate the Acceleration When It is at 4 Cm from Its Positive Extreme Position. Concept: Simple Harmonic Motion.
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