HSC Science (General) 12th Board ExamMaharashtra State Board
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# Solution - Calculate the Acceleration When It is at 4 Cm from Its Positive Extreme Position. - HSC Science (General) 12th Board Exam - Physics

ConceptSimple Harmonic Motion

#### Question

A particle in S.H.M. has a period of 2 seconds and amplitude of 10 cm. Calculate the acceleration when it is at 4 cm from its positive extreme position.

#### Solution

A particle in SHM has a period of 2 seconds and an amplitude of 10 cm. When it is at 4 cm from its positive extreme position, the displacement (x) of the particle is 10 - 4 = 6 cm.

Acceleration = ω2.x (in magnitude)

=((2pi)/T)^2x

=(4pi^2)/(2)^2xx 6

= 59.16 cm/s2

Thus, the acceleration of the particle at 4 cm from its positive extreme position is 59.16 cm/s2.

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#### Reference Material

Solution for question: Calculate the Acceleration When It is at 4 Cm from Its Positive Extreme Position. concept: null - Simple Harmonic Motion. For the courses HSC Science (General) , HSC Science (Electronics), HSC Science (Computer Science)
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