Q 1.2 - ICSE Class 10 - Mathematics
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Here, a, b, c are in G.P.
⇒ b2 = ac
⇒ (b2)n = (ac)n
⇒ b2n = ancn
Taking log on both sides, we get
log (b2n) = log (ancn)
⇒ log(bn)2 = log an + log cn
⇒ 2log bn = log an + log cn
⇒ log bn + log bn = log an + log cn
⇒ log bn - log an = log cn - log bn
⇒ log an, log bn and log cn are in A.P.
Is there an error in this question or solution?
Solution Q 1.2 Concept: Simple Applications - Geometric Progression.