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In the following figure, DE || OQ and DF || OR, show that EF || QR - CBSE Class 10 - Mathematics

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Question

In the following figure, DE || OQ and DF || OR, show that EF || QR

Solution

In Δ POQ, DE || OQ

`:. (PE)/(EQ) = (PD)/(DO)` .... (Basic Proportionality theorem)  (i)

In ΔPOR, DF || OR

`:. (PF)/(FR) = (PD)/(DO)` (Basic Proportionality theorem)  (ii)

From i and ii we obtain

`(PE)/(EQ) = (PF)/(FR)`

:. EF || QR (Converse of basic proportionally theorem)

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 10 (2019 to Current)
Chapter 6: Triangles
Ex. 6.20 | Q: 5 | Page no. 129
Solution In the following figure, DE || OQ and DF || OR, show that EF || QR Concept: Similarity of Triangles.
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