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ConceptSimilarity Examples and Solutions

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#### Question

P and Q are points on sides AB and AC respectively of ∆ABC. If AP = 3 cm, PB = 6cm. AQ = 5 cm and QC = 10 cm, show that BC = 3PQ.

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#### Similar questions VIEW ALL

In figure, considering triangles BEP and CPD, prove that BP × PD = EP × PC.

In ∆ABC, DE is parallel to base BC, with D on AB and E on AC. If `\frac{AD}{DB}=\frac{2}{3}` , find `\frac{BC}{DE}.`

Through the mid-point M of the side CD of a parallelogram ABCD, the line BM is drawn intersecting AC in L and AD produced in E. Prove that EL = 2 BL

The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA

In figure, ∠A = ∠CED, prove that ∆CAB ~ ∆CED. Also, find the value of x.

#### Reference Material

Solution for concept: Similarity Examples and Solutions. For the course 8th-10th CBSE