# Solution - Similarity Examples and Solutions

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ConceptSimilarity Examples and Solutions

#### Question

P and Q are points on sides AB and AC respectively of ∆ABC. If AP = 3 cm, PB = 6cm. AQ = 5 cm and QC = 10 cm, show that BC = 3PQ.

#### Solution

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In figure, considering triangles BEP and CPD, prove that BP × PD = EP × PC.

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In ∆ABC, DE is parallel to base BC, with D on AB and E on AC. If \frac{AD}{DB}=\frac{2}{3} , find \frac{BC}{DE}.

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#### Reference Material

Solution for concept: Similarity Examples and Solutions. For the course 8th-10th CBSE
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