shaalaa.com
S

Solution - Similarity Examples and Solutions

Account
User


Login
Register


      Forgot password?
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

Question

The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA

Solution

You need to to view the solution
Is there an error in this question or solution?

Similar questions VIEW ALL

In figure, `\frac{AO}{OC}=\frac{BO}{OD}=\frac{1}{2}` and AB = 5 cm. Find the value of DC.

view solution

In figure, ∠BAC = 90º and segment AD ⊥ BC. Prove that AD2 = BD × DC.

view solution

In figure, considering triangles BEP and CPD, prove that BP × PD = EP × PC.

view solution

In ∆ABC, DE is parallel to base BC, with D on AB and E on AC. If `\frac{AD}{DB}=\frac{2}{3}` , find `\frac{BC}{DE}.`

view solution

In figure, if ∠A = ∠C, then prove that ∆AOB ~ ∆COD

 

view solution

Content BooksVIEW ALL [1]

Reference Material

Solution for concept: Similarity Examples and Solutions. For the course 8th-10th CBSE
S