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Sum
सिद्ध कीजिए:
`2sin^-1 3/5 = tan^-1 24/7`
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Solution
= `2sin^-1 3/5 = 2tan^-1 3/sqrt(5^2 - 3^2)` ...`[sin^-1 "p"/"h" = tan^-1 "p"/sqrt("h"^2 - "p"^2)]`
= `2tan^-1 3/4`
= `tan^-1 (2 xx 3/4)/(1 - (3/4)^2)` ...`[2tan^-1 = tan^-1 (2x)/(1 - x^2)]`
= `tan^-1 (3/2)/(7/16)`
`= tan^-1 24/7`
Concept: प्रतिलोम त्रिकोणमितीय फलन की आधारभूत संकल्पनाएँ
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