Advertisement
Advertisement
Advertisement
Show that:
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
Advertisement
Solution
`{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))=x`
LHS = `{(x^(a-a^-1))^(1/(a-1))}^(a/(a+1))`
`={(x^(a-1/a))^(1/(a-1)xxa/(a+1))}`
`={x^((a^2-1)/a)}^(a/(a^2-1))`
`=x^((a^2-1)/axxa/(a^2-1))`
`=x^1`
`= x`
= RHS
Concept: Laws of Exponents for Real Numbers
Is there an error in this question or solution?