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Show that the Value of X is 11, When - ICSE Class 10 - Mathematics

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Question

Show that the value of x is 11, when `("x"^3 + "3x")/(3"x"^2 + 1) = 341/91`

Solution

`("x"^3 + "3x")/(3"x"^2 + 1) = 341/91`

⇒  91(x3 + 3x) = 341(3x2 + 1) 

⇒  91x3 - 1023x2 + 273x - 341 = O 

LHS

91x3 - 1023x2 + 273x - 341 

= 91( 11 × 11 × 11) - 1023 (11 × 11) + 273 (11) -341 

= (91 × 1331) - (1023 ×  121) + (273 × 11) - 341 

= 121121 - 123783 + 3003 - 341 

= 0= RHS  

LHS = RHS. 

Hence x = 11 

  Is there an error in this question or solution?

APPEARS IN

 Frank Solution for Frank Class 10 Mathematics Part 2 (2016 to Current)
Chapter 9: Ratio and Proportion
Exercise 9.3 | Q: 15

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Solution Show that the Value of X is 11, When Concept: Ratio and Proportion Example.
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