Sum

Show that the relation R on R defined as R = {(a, b): a ≤ b}, is reflexive, and transitive but not symmetric.

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#### Solution

R = {(a, b); a ≤ b}

Clearly (a, a) ∈ R as a = a.

**∴**R is reflexive.

Now,

(2, 4) ∈ R (as 2 < 4)

But, (4, 2) ∉ R as 4 is greater than 2.

**∴**R is not symmetric.

Now,

let (a, b), (b, c) ∈ R.

Then,

a ≤ b and b ≤ c

⇒ a ≤ c

⇒ (a, c) ∈ R

**∴**R is transitive.

Hence, R is reflexive and transitive but not symmetric.

Concept: Types of Relations

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