Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 9th
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Show that the point (11, 2) is the centre of the circle passing through the points (1, 2), (3, −4) and (5, −6) - Mathematics

Sum

Show that the point (11, 2) is the centre of the circle passing through the points (1, 2), (3, −4) and (5, −6)

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Solution


Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`

OA = `sqrt((11 - 1)^2 + (2 - 2)^2`

= `sqrt(10^2 + 0^2)`

= `sqrt(100)`

= 10

OB = `sqrt((11 - 3)^2 + (2 + 4)^2`

= `sqrt(8^2 + 6^2)`

= `sqrt(64 + 36)`

= `sqrt(100)`

= 10

OC = `sqrt((11 - 5)^2 + (2 + 6)^2`

= `sqrt(6^2 + 8^2)`

= `sqrt(36 + 64)`

= `sqrt(100)`

= 10

OA = OB = OC = 10

O is the centre of the circle passing through A, B and C.

Concept: Co-ordinates of Points and Distance
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APPEARS IN

Samacheer Kalvi Mathematics Class 9th Tamil Nadu State Board
Chapter 5 Coordinate Geometry
Exercise 5.2 | Q 11 | Page 203
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