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Sum

**Show that the following statement pattern is contingency.**

(p∧~q) → (~p∧~q)

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#### Solution

p |
q |
~p |
~q |
p∧~q |
~p∧~q |
(p∧~q)→(~p∧~q) |

T | T | F | F | F | F | T |

T | F | F | T | T | F | F |

F | T | T | F | F | F | T |

F | F | T | T | F | T | T |

The truth values in the last column are not identical. Hence, it is **contingency**.

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