Show that the right circular cone of least curved surface and given volume has an altitude equal to `sqrt2` time the radius of the base.
Let r and h be the radius and the height (altitude) of the cone respectively.
Then, the volume (V) of the cone is given as:
The surface area (S) of the cone is given by,
S = πrl (where l is the slant height)
Hence, for a given volume, the right circular cone of the least curved surface has an altitude equal to `sqrt2` times the radius of the base.