Show that the lines `(x+1)/3=(y+3)/5=(z+5)/7 and (x−2)/1=(y−4)/3=(z−6)/5` intersect. Also find their point of intersection
x=3λ−1, y=5λ−3 and z=7λ−5
So, the coordinates of a general point on this line are (3λ−1, 5λ−3, 7λ−5).
The equation of the second line is given below:
x=μ+2, y=3μ+4 and z=5μ+6
So, the coordinates of a general point on this line are (μ+2, 3μ+4, 5μ+6).
If the lines intersect, then they have a common point.
So, for some values of λ and μ, we must have:
3λ−1=μ+2, 5λ−3=3μ+4 and 7λ−5=5μ+6
⇒ 3λ−μ=3, 5λ−3μ=7 and 7λ−5μ=11
Solving the first two equations, 3λ−μ=3 and 5λ−3μ=7, we get:
λ=1/2 and μ=−3/2
Since λ=1/2 and μ=−3/2 satisfy the third equation, 7λ−5μ=11, the given lines intersect each other.
When λ=1/2 in (3λ−1, 5λ−3, 7λ−5), the coordinates of the required point of intersection are (1/2, −1/2, −3/2)