#### Question

Show that the function f: ℝ → ℝ defined by f(x) = `x/(x^2 + 1), ∀x in R`is neither one-one nor onto. Also, if g: ℝ → ℝ is defined as g(x) = 2x - 1. Find fog(x)

#### Solution

Given `y = x/(x^2+1)`

`=> yx^2 - x + y = 0`

Here a = y, b = -1 and c = y

`:. x = (-(-1)+- sqrt(1-4y^2))/(2y)`

Clearly for every value of y, x will have two different values so the function is many−one not one−one

Since `1 -4y^2 >= 0 => (1+2y)(1-2y)>= 0 => (-1)/2 <= y ><= 1/2`

That means no matter what is x, y always belongs to the interval `[(-1)/2, 1/2]`

So, the function is not onto

Now, fog(x) = `(2x-1)/((2x-1)^2 +1) = (2x+1)/(4x^2 - 4x + 1+1) = (2x+1)/(2(2x^2 - 2x + 1))`

Is there an error in this question or solution?

Solution Show that the Function F: ℝ → ℝ Defined by F(X) = `X/(X^2 + 1), ∀X in R`Is Neither One-one Nor Onto. Also, If G: ℝ → ℝ is Defined as G(X) = 2x - 1. Find Fog(X) Concept: Types of Functions.