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Select the most appropriate option. For vaporization of water at 1 bar, ΔH = 40.63 kJ mol–1 and ΔS = 108.8 J K–1 mol–1 . At what temperature, ΔG = 0? - Chemistry

MCQ

Select the most appropriate option.

For vaporization of water at 1 bar, ΔH = 40.63 kJ mol–1 and ΔS = 108.8 J K–1 mol–1 . At what temperature, ΔG = 0?

Options

  • 273.4 K

  • 393.4 K

  • 373.4 K

  • 293.4 K

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Solution

373.4 K

Explanation:

Temperature at which reaction is at equilibrium (ΔG = 0) is,

T = `(triangle "H")/(triangle "S") = (40.63  "kJ mol"^-1)/(108.8 xx 10^-3 "kJ K"^-1) = 373.4  "K"`

Concept: Chemical Thermodynamics
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APPEARS IN

Balbharati Chemistry 12th Standard HSC for Maharashtra State Board
Chapter 4 Chemical Thermodynamics
Exercise | Q 1.09 | Page 87
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