Advertisement Remove all ads

# Select the correct answer from the given alternative: If f(x) =x2+sinx+1for x≤0=x2-2x+1for x≤0 then - Mathematics and Statistics

MCQ

Select the correct answer from the given alternative:

If f(x) {:( = x^2 + sin x + 1, "for"  x ≤ 0),(= x^2 - 2x + 1, "for"  x ≤ 0):} then

#### Options

• f is continuous at x = 0, but not differentiable at x = 0

• f is neither continuous nor differentiable at x = 0

• f is not continuous at x = 0, but differentiable at x = 0

• f is both continuous and differentiable at x = 0

Advertisement Remove all ads

#### Solution

f is continuous at x = 0, but not differentiable at x = 0

Explanation;

f(x) {:( = x^2 + sin x + 1,","  x ≤ 0),(= x^2 - 2x + 1,","  x ≤ 0):}

lim_(x -> 0^-) "f"(x) = lim_(x -> 0^-) (x^2 + sinx + 1) = 0 + 0 + 1 = 1

lim_(x -> 0^+) "f"(x) = lim_(x -> 0^+) (x^2 - 2x + 1) = 0 – 0 + 1 = 1

∴ f is continuous at x = 0

Lf'(0) = lim_("h" -> 0^-) ("f"(0 + "h") - "f"(0))/"h"

= lim_("h" -> 0^-) ("h"^2 + sin "h" + 1 - (0 + 0 + 1))/"h"

= lim_("h" -> 0^-) ("h" + sin"h"/"h") = 0 + 1 = 1

Rf'(0) = lim_("h" -> 0^+) ("f"(0 + "h") - "f"(0))/"h"

= lim_("h" -> 0^+) ("h"^2 - 2"h" + 1 - 1)/"h"

= lim_("h" -> 0) ("h" - 2)

= – 2

∵ Rf'(0) ≠ Lf'(0)

∴ f is not differentiable at x = 0.

Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

Balbharati Mathematics and Statistics 2 (Arts and Science) 11th Standard Maharashtra State Board
Chapter 9 Differentiation
Miscellaneous Exercise 9 | Q I. (7) | Page 195
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?