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Sec 50º Sin 40° + Cos 40º Cosec 50º - Mathematics

Sum

Evaluate the following 

sec 50º sin 40° + cos 40º cosec 50º 

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Solution

We have,

sec50º sin40º + cos40º cosec50º

= sec(90º – 40º) sin40º + cos40º cosec(90º – 40º)

= cosec40º sin40º + cos40ºsec40º

`=\frac{\sin 40^\text{o}}{\sin 40^\text{o}}+\frac{\cos 40^\text{o}}{\cos40^\text{o}}`

= 1 + 1 = 2

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APPEARS IN

RD Sharma Class 10 Maths
Chapter 10 Trigonometric Ratios
Exercise 10.3 | Q 2.11 | Page 53
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