#### Question

A solid sphere of mass 1 kg rolls on a table with linear speed 2 m/s, find its total kinetic energy.

#### Solution

Solution:

Given: m = 1kg, v = 2 m/s

To find: Total K.E

`E=1/2mv^2[1+k^2/R^2]`

for a solid sphere, `k^2=(2/5)R^2`

`therefore E=1/2 mv^2[1+(2/5R^2)/R^2]`

`therefore E=1/2xx7/5xxmv^2`

`therefore E=1/2xx7/5xx1xx2^2`

`therefore E=14/5`

`therefore E=2.8J`

The total kinetic energy of the solid sphere is `2.8J`

Is there an error in this question or solution?

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A Solid Sphere of Mass 1 Kg Rolls on a Table with Linear Speed 2 M/S, Find Its Total Kinetic Energy. Concept: Rolling Motion.

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