HSC Science (General) 12th Board ExamMaharashtra State Board
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

An A.C. Circuit Consists of Inductor of Inductance 125 Mh Connected in Parallel with a Capacitor of Capacity 50 μF. Determine the Resonant Frequency. - HSC Science (General) 12th Board Exam - Physics

Login
Create free account


      Forgot password?

Question

An A.C. circuit consists of inductor of inductance 125 mH connected in parallel with a capacitor of capacity 50 μF. Determine the resonant frequency.

Solution

L = 125 mH = 125 × 10−3H,
C = 50 µF = 50 × 10−6F
fr = ?
We have,

= antilog [log (400) – log (6.28)]
= antilog [2.6021 – 0.7980]
= antilog [1.8041]
∴ fr = 63.69 Hz

The resonant frequency in the A.C. circuit is 63.69 Hz.

  Is there an error in this question or solution?

APPEARS IN

 2013-2014 (October) (with solutions)
Question 6.7 | 2.00 marks

Video TutorialsVIEW ALL [1]

Solution An A.C. Circuit Consists of Inductor of Inductance 125 Mh Connected in Parallel with a Capacitor of Capacity 50 μF. Determine the Resonant Frequency. Concept: Resonant Circuit.
S
View in app×