#### Question

The numerical aperture of objective of a microscope is 0.12. The limit of resolution, when light of wavelength 6000A is used to view an object is.......................

- 0.25 * 10
^{-7}m - 2.5 * 10
^{-7}m - 25 * 10
^{-7}m - 250 * 10
^{-7}m

#### Solution

(c) 25 * 10^{-7}m

The minimum resolvable linear distance between two nearby objects is given by

`"x"=lambda/(2"NA")=(6000xx10^-10)/(2xx0.12)=2.5xx10^-6"m"=25xx10^-7"m"`

Is there an error in this question or solution?

#### APPEARS IN

Solution The Numerical Aperture of Objective of a Microscope is 0.12. the Limit of Resolution, When Light of Wavelength 6000A is Used to View an Object is Concept: Resolving Power of a Microscope and Telescope.