#### Question

V = IRTwo resistances X and Y are connected turn by turn : (i) in parallel, and (ii) series. In which case the resultant resistance will be less than either of the individual resistances?R = R_{1}+ R_{2}+ R_{3}

#### Solution

When two resistors, X and Y are connected in parallel combination, the total resistance will be less than the individual resistance. The total resistance in a parallel arrangement is given by:

`1/R=1/R_1+1/R_2`

where as in a series combination, the total resistance is more than the individual resistances. The total resistance in a series combination is given by:

R = *R _{1}*+

*R*

_{2} Is there an error in this question or solution?

Solution When Two Resistors, X and Y Are Connected in Parallel Combination, the Total Resistance Will Be Less than the Individual Resistance. the Total Resistance in a Parallel Arrangement is Given By: 1 R = 1 R 1 + 1 R 2 Where as in a Series Combination, the Total Resistance is More than the Individual Resistances. the Total Resistance in a Series Combination is Given By: R = R1+ R2 Concept: Resistance of a System of Resistors - Resistors in Series.