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Sum
Represent the following situations in the form of quadratic equations.
A train travels a distance of 480 km at a uniform speed. If the speed had been 8 km/h less, then it would have taken 3 hours more to cover the same distance. We need to find the speed of the train.
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Solution
Let the speed of the train be x km/h.
Time taken to travel 480 km = 480/x km/h
In second condition, let the speed of train = (x - 8) km/h
It is also given that the train will take 3 hours to cover the same distance.
Therefore, time taken to travel 480 km = `(480/x + 3) `
Speed × Time = Distance
⇒ `(x - 8)(480/x + 3) = 480`
`⇒ 480 + 3x - 3840/x - 24 = 480`
⇒ 3x - 3840/x = 24
⇒ 3x2 - 24x - 3840 = 0
⇒ x2 - 8x - 1280 = 0
⇒ ax2 + bx + c = 0
`x = (-b ± sqrt(b^2 - 4ac))/(2a)`
x = `(8 ± sqrt(64 + 4(1280)))/2`
= `(8 ± 72)/2`
= 40 km/hr
Concept: Quadratic Equations
Is there an error in this question or solution?