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Find the remainder when x^3 + 3x^2 + 3x + 1 is divided by x + π. - CBSE Class 9 - Mathematics

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Question

Find the remainder when x3 + 3x2 + 3x + 1 is divided by x + π.

Solution 1

Let p(x) = x3 + 3x2 + 3x + 1

x + π = 0 ⇒ x = -π

∴ Remainder = (-π)3 + 3(-π)2 - 3(-π) + 1

                   = -π3 + 3π2 - 3π + 1

Therefore, the remainder is -π3 + 3π2 - 3π + 1.

Solution 2

By long division,

Therefore, the remainder is -π3 + 3π2 - 3π + 1.

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Solution Find the remainder when x^3 + 3x^2 + 3x + 1 is divided by x + π. Concept: Remainder Theorem.
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