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The Sum of Three Numbers in G.P. is 56. If We Subtract 1, 7, 21 from These Numbers in that Order, We Obtain an Arithmetic Progression. Find the Numbers. - CBSE (Arts) Class 11 - Mathematics

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Question

The sum of three numbers in G.P. is 56. If we subtract 1, 7, 21 from these numbers in that order, we obtain an arithmetic progression. Find the numbers.

Solution

Let the three numbers in G.P. be aar, and ar2.

From the given condition, a + ar + ar2 = 56

⇒ a (1 + r + r2) = 56

a – 1, ar – 7, ar2 – 21 forms an A.P.

∴(ar – 7) – (a – 1) = (ar2 – 21) – (ar – 7)

⇒ ar – a – 6 = ar– ar – 14

ar– 2ar + a = 8

ar– ar – ar + a = 8

a(r+ 1 – 2r) = 8

⇒ (r – 1)2 = 8 … (2)

⇒7(r2 – 2r + 1) = 1 + r + r2

⇒7r2 – 14 r + 7 – 1 – r – r2 = 0

⇒ 6r2 – 15r + 6 = 0

⇒ 6r2 – 12r – 3r + 6 = 0

⇒ 6r (r – 2) – 3 (r – 2) = 0

⇒ (6r – 3) (r – 2) = 0

  Is there an error in this question or solution?

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 NCERT Solution for Mathematics Textbook for Class 11 (2018 to Current)
Chapter 9: Sequences and Series
Q: 10 | Page no. 199
Solution The Sum of Three Numbers in G.P. is 56. If We Subtract 1, 7, 21 from These Numbers in that Order, We Obtain an Arithmetic Progression. Find the Numbers. Concept: Relationship Between A.M. and G.M..
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