2ag (S) + 2h^(+) (0.1 M) + 2cl^(-) (0.1 M) Triangleg^0 = -43600 J at 25^@ C Calculate the E.M.F. of the Cell - Chemistry | Shaalaa.com" /> 2ag (S) + 2h^(+) (0.1 M) + 2cl^(-) (0.1 M) Triangleg^0 = -43600 J at 25^@ C Calculate the E.M.F. of the Cell Concept: Relation Between Gibbs Energy Change and Emf of a Cell." /> 2ag (S) + 2h^(+) (0.1 M) + 2cl^(-) (0.1 M) Triangleg^0 = -43600 J at 25^@ C Calculate the E.M.F. of the Cell" />
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# For the Reaction 2agcl (S) + H_2 (G) ("1 Atm") -> 2ag (S) + 2h^(+) (0.1 M) + 2cl^(-) (0.1 M) Triangleg^0 = -43600 J at 25^@ C Calculate the E.M.F. of the Cell - Chemistry

#### Question

For the reaction

2AgCl (s) + H_2 (g) ("1 atm") -> 2Ag (s) + 2H^(+)  (0.1 M) +  2Cl^(-) (0.1 M)

triangleG^0 = -43600 J at 25^@ C

Calculate the e.m.f. of the cell

[log 10^(-n) = -n]

#### Solution

triangleG^0 = -nFE_(cell)^0

:. E_(cell)^0 = 0.226 V

E_(cell) = 0.226 - (0.059)/2 log (0.1)^2 (0.1)^2

Therefore, E_(cell) = 0.226 - (0.059)/2 log 10^(-4)

= 0.226 + 0.059 x 2

= 0.344 V

Is there an error in this question or solution?
For the Reaction 2agcl (S) + H_2 (G) ("1 Atm") -> 2ag (S) + 2h^(+) (0.1 M) + 2cl^(-) (0.1 M) Triangleg^0 = -43600 J at 25^@ C` Calculate the E.M.F. of the Cell Concept: Relation Between Gibbs Energy Change and Emf of a Cell.