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Solution - An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image. - CBSE Class 10 - Science

ConceptImage Formation in Lenses Using Ray Diagrams - Convex Lens

Question

An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image.

Solution

Object distance, u= – 20 cm
Object height, h= 5 cm
Radius of curvature, R= 30 cm
Radius of curvature = 2 × Focal length
R= 2f
f= 15 cm
According to the mirror formula,

`1/v-1/u=1/f`

`1/v=1/f-1/u`

`=1/15+1/20=(4+3)/60=7/60`

The positive value of v indicates that the image is formed behind the mirror.

Magnificatiom m=`"Image Distance"/"Object Distance"=-8.57/(-20)=0.428`

The positive value of magnification indicates that the image formed is virtual

Magnificatiom m=`"Height of image"/"Height of Object"=(h')/h`

h'=m x h=0.428 x 5=2.14 cm

The positive value of image height indicates that the image formed is erect.
Therefore, the image formed is virtual, erect, and smaller in size.

Is there an error in this question or solution?

APPEARS IN

 NCERT Science Textbook for Class 10 (with solutions)
Chapter 10: Light - Reflection and Refraction
Q: 14 | Page no. 186

Reference Material

Solution for question: An object 5 cm is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position, nature and size of the image. concept: null - Image Formation in Lenses Using Ray Diagrams - Convex Lens. For the course CBSE
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