# Ravish Wanted to Make a Temporary Shelter for His Car by Making a Box-like Structure with Tarpaulin that Covers All the Four Sides and the Top of the Car - Mathematics

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car ( with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with
base dimensions 4 m × 3m?

#### Solution

Given that

Shelter length = 4m
Height = 2.5m
The tarpaulin will be required for four sides of the shelter

Area of tarpaulin in required=2(lb+bh+hl)

=[2(4)xx2.5+(3xx2.5)+4xx3]m^2

=[2(10+7.5)+12]m^2

47m^2=47m^2

Concept: Surface Area of a Cuboid
Is there an error in this question or solution?
Chapter 18: Surface Areas and Volume of a Cuboid and Cube - Exercise 18.1 [Page 14]

#### APPEARS IN

RD Sharma Mathematics for Class 9
Chapter 18 Surface Areas and Volume of a Cuboid and Cube
Exercise 18.1 | Q 12 | Page 14

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