HSC Science (General) 12th Board ExamMaharashtra State Board
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# Solution for From the Following Data for the Liquid Phase Reaction a → B, Determine the Order of Reaction and Calculate Its Rate Constant - HSC Science (General) 12th Board Exam - Chemistry

#### Question

From the following data for the liquid phase reaction A → B, determine the order of reaction
and calculate its rate constant

 t/s 0 600 1200 1800 [A]/molL^-1 0.624 0.446 0.318 0.226

#### Solution

Calculation:
We require to calculate the rate constant at different time intervals.

k=(2.303)/t log_10[ [A]_0/[A]_t]       ...........[Integrated rate law for first order reaction]

A.

[A]_0=0.624

[A]_(t1)=0.446

t1=600s

k_1=2.303/t_1 log[[A]_0/[A]_t]

k_1=2.303/600 log [0.624/0.446]

k_1=3.838xx10^-3 log[1.399]

k_1=3.838xx10^-3xx0.1458

therefore k_1=5.596xx10^-4 s^-1

B.

[A]_0=0.624

[A]_t=0.318

t_2=1200s

k_2=2.303/t_2 log_10[0.624/0.318]

k_2=1.919xx10^-3 log(1.962)

k_2=1.919xx10^3xx0.2927

k_2=5.617xx10^-4 s^-1

C.

[A]_0=0.624

[A]_(t3)=0.226

t_3=1800 s

k_3=2.303/1800 log[0.624/0.226]

k_3=1.279xx10^-3xx0.4411

k_3=5.641xx10^-4s^-1

k=(k_1+k_2+k_3)/3=((5.596xx10^-4)+(5.617xx10^-4)+(5.641xx10^-4))/3

k=5.618xx10^-4 s^-1

All the k values calculated at different time intervals are almost the same. This implies that the reaction obeys the integrated rate equation of first order reaction. Hence, the reaction is a first order reaction.

Is there an error in this question or solution?

#### APPEARS IN

2016-2017 (July) (with solutions)
Question 3.1 | 3.00 marks

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Solution From the Following Data for the Liquid Phase Reaction a → B, Determine the Order of Reaction and Calculate Its Rate Constant Concept: Rate of a Chemical Reaction.
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