#### Question

A car is travelling along the road at 8 ms^{-1}. It accelerates at 1 ms^{-2} for a distance of 18 m. How fast is it then travelling ?

#### Solution

We have to find the final velocity of the moving object. And we have the following information

Initial velocity, (u) = 8 m/s

Acceleration, (a) = 1 m/s^{2}

Distance, (s) = 18 m

So applying 3^{rd} equation of motion to calculate the final velocity,

`ν = sqrt(u^2 + 2as)`

Where,

(a) - Acceleration

(ν) - Final velocity

(u) - Initial velocity

(s) - Distance

Put the values in the above equation to get the value of final velocity,

`ν = sqrt(64 + 36)` m/s

= `sqrt(100)` m/s

= 10 m/s

Is there an error in this question or solution?

Solution A Car is Travelling Along the Road at 8 Ms-1. It Accelerates at 1 Ms-2 for a Distance of 18 M. How Fast is It Then Travelling ? Concept: Rate of Change of Velocity.