PUC Karnataka Science Class 12Department of Pre-University Education, Karnataka
Share
Notifications

View all notifications
Books Shortlist
Your shortlist is empty

# Solution for The Side of a Square is Increasing at the Rate of 0.1 Cm/Sec. Find the Rate of Increase of Its Perimeter ? - PUC Karnataka Science Class 12 - Mathematics

Login
Create free account

Forgot password?

#### Question

The side of a square is increasing at the rate of 0.1 cm/sec. Find the rate of increase of its perimeter ?

#### Solution

$\text { Let x be the side and P be the perimeter of the square at any timet. Then },$
$P = 4x$
$\Rightarrow \frac{dP}{dt} = 4\frac{dx}{dt}$
$\Rightarrow \frac{dP}{dt} = 4 \times 0 . 1 \left[ \because\frac{dx}{dt}=0.1 cm/sec \right]$
$\Rightarrow \frac{dP}{dt} = 0 . 4 cm/\sec$

Is there an error in this question or solution?

#### Video TutorialsVIEW ALL [3]

Solution The Side of a Square is Increasing at the Rate of 0.1 Cm/Sec. Find the Rate of Increase of Its Perimeter ? Concept: Rate of Change of Bodies Or Quantities.
S