#### Question

A man 2 metres tall walks away from a lamp post 5 metres height at the rate of 4.8 km/hr. The rate of increase of the length of his shadow is

1.6 km/hr

6.3 km/hr

5 km/hr

3.2 km/hr

#### Solution

Let AB be the lamp post. Suppose at any time t, the man CD be at a distance of x km from the lamp post and y m be the length of his shadow CE.

\[\text { Since triangles ABE and CDE are similar }, \]

\[\frac{AB}{CD} = \frac{AE}{CE}\]

\[\Rightarrow \frac{5}{2} = \frac{x + y}{y}\]

\[ \Rightarrow \frac{x}{y} = \frac{5}{2} - 1\]

\[ \Rightarrow \frac{x}{y} = \frac{3}{2}\]

\[ \Rightarrow y = \frac{2}{3}x\]

\[ \Rightarrow \frac{dy}{dt} = \frac{2}{3}\left( \frac{dx}{dt} \right)\]

\[ \Rightarrow \frac{dy}{dt} = \frac{2}{3} \times 4 . 8\]

\[ \Rightarrow \frac{dy}{dt} = 3 . 2 \ km/hr\]

Is there an error in this question or solution?

Solution A Man 2 Metres Tall Walks Away from a Lamp Post 5 Metres Height at the Rate of 4.8 Km/Hr. the Rate of Increase of the Length of His Shadow is (A) 1.6 Km/Hr (B) 6.3 Km/Hr(C) 5 Km/Hr (D) 3.2 Km/Hr Concept: Rate of Change of Bodies Or Quantities.